Free Sample Questions for the digital TestAS Core Test

The correct answers are A1 and B3.

The black triangle moves clockwise along the outer edge of the grid, skipping one cell at each step.

The correct answers are A1 and B2.

This task can only be solved correctly by identifying the rules that govern the movements of the shapes across the grid sequence.

• The blue square moves counterclockwise in a circular path around the center of the grid.
• The triangle moves along the outer edge of the grid, also counterclockwise. It skips one cell with each move and alternates its color between black and white at every step.

Based on these two rules, we can predict how the shapes continue from the last given grid:

The blue square moves one step downward (A), then one step to the right (B).
The triangle moves two steps to the right, changing from white to black (A), then two steps upward, changing back to white (B).

In this task, three symbols move through the grid following fixed patterns:

• The yellow arrow moves one step clockwise along the outer edge of the grid with each turn.
• The blue diamond moves two steps clockwise along the outer edge.
• The grey star moves one step downward at a time. When it reaches the bottom edge, it bounces back and moves one step upward with each following move.

These movement patterns lead to the correct continuation of the sequence in A1 and B2.

The correct answers are A2 and B1.

To continue the sequence correctly, you need to identify the specific movement pattern of each figure. Each shape follows its own logic. In detail:

Black triangle:
The black triangle moves diagonally from the top left to the bottom right and then back.
Any option where the triangle is not on this diagonal must be excluded.
Possible positions: A1, A2, B1, B2, B3

Red star:
The star alternates its appearance with each step: filled (★), empty (☆), filled, empty, etc.
At the same time, it moves clockwise along the outer edge of the grid, skipping one cell each time.
Possible positions: A1, A2, B1, B3
B2 must be excluded (star is in the wrong position)

Blue square:
The square moves diagonally from the bottom left to the top right and back.
Possible positions: A2, A3, B1, B2
Since A3 and B2 are already ruled out, A2 and B1 remain.

Yellow circle (for verification):
The yellow circle moves up and down within the third column.
A2 and B1 show the circle in the correct position.

Conclusion:
Correct solution: A2 and B1

This combination is the only one that correctly continues all four movement patterns and also accounts for the alternating appearance of the red star.

Start by solving the second equation:

A + 3 = 13

A = 13 – 3 = 10

Step 1:
The first equation already defines B in terms of A:
  B = A + 2

Step 2:
Substitute the expression for B into the second equation:
  C = (A + 2) + 5 = A + 7

Step 3:
Now substitute the expressions for B and C into the third equation:
  A + (A + 2) + (A + 7) = 24

Step 4:
Simplify the equation:
  3A + 9 = 24

Step 5:
Solve the equation for A:
  3A = 24 − 9 = 15
  A = 15 / 3 = 5

Step 6:
Calculate the missing unknowns: 
  B = A + 2 = 5 + 2 = 7
  C = A + 7 = 5 + 7 = 12

Solutions:
A = 5, B = 7, C = 12

Correct answer: 12

Substitute the second equation into the third equation to get:

A = 2 · C – 2 · B 

A = 2 · (B + 2) – 2 · B 

A = 2B + 4 – 2B 

A = 4

Now substitute the expression for C from the second equation into the first equation to solve for B:

A · C = 12

4 · (B +2) = 12

4B + 8 = 12

4B = 4

B = 1

Final values:
A = 4, B = 1, C = B + 2 = 3

Correct answer: 3

Since all other equations can be expressed in terms of B, substitute them into the first equation to solve for B.

A + B + C – D = 19

(4 · B) + B + (8 · B) – (5 + B) = 19

4B + B + 8B – 5 – B = 19

12B = 24

B = 2

Now use B = 2 to calculate the values of A, C, and D:

C = 8 · B

C = 8 · 2

C = 16

A = 4 · B

A = 4 · 2

A = 8

D = 5 + B

D = 5 + 2

D = 7

Correct answer: 7

The correct answer is A.

Because there are already Bs in the top row and in the fourth row, the B in the last column must be added mentally in the bottom row.

Because there is already an E in the last column of the second row, the E in the first column must be added mentally in the bottom row.

There are already Ds in the second and fourth columns. Therefore, the D in the bottom row can only be added mentally in the centre column.

There is already an A in the fourth column, so it can only be the letter you are looking for in the bottom row.

Therefore, the correct answer is A.

The correct answer is: D.

Because there is already an A in the second row, the C in the fourth column must be added mentally in the bottom row.

There is already A in the second, middle and last column. Therefore, the A in the bottom row can only be added in the first column.

There are already Es in the second and last column. Therefore, the E in the bottom row can only be added in the centre column.

There is already a D in the middle row. Therefore, the D in the centre column can only be the letter you are looking for.

Therefore, the correct answer is D.

The correct answer is: A.

Because there is already an E in the middle row of the fourth column, the E in the top row must be added mentally in the last column.

There is already an A in the centre column of the middle row. Therefore, the A can only be the object you are looking for in the fourth row in the last column.

Therefore, the correct answer is A.

The letters B, D and E are missing in the second row.

B and D are missing in the second column.

As there is already a B in the first row, the B in the second row belongs in the second column.

Now only the letters D and E are missing in the second row.

As there is already an E in the last column, the E in the second row must be placed in the penultimate column.

So the correct answer is: E.